Quiz 5 Ma 322 005 Name ______________
1. Find a basis for the column space of A = What is the dimension of N(A)?
By inspection, the first and third columns of A are the pivot columns and so form a basis for the column space. So the dimension of C(A) is 2. Since dim(C(A))+dim(N(A)) = #cols of A = 3, we get that dim(N(A))=1. (Note: this could also be computed directly by finding a basis for N(A).
2. Suppose that V is a vector space with basis . Let and w = . Show that u and w are linearly independent.
Write s u + t w = O and show that s = 0 = t.
Well s u + t w = s ( ) + t ( ) = = O. Since and are linearly independent, and . Adding, we get , so s = 0. Substitute s = 0 into 1st eqn and get t = 0. Hence u and w are linearly independent.
3. Let and . Explain why and cannot form a basis for
The dimension of is 4 and hence any basis for must have 4 vectors.